5x/(5x^2)+10x

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Solution for 5x/(5x^2)+10x equation: 


D( x )

5*x^2 = 0

5*x^2 = 0

5*x^2 = 0

5*x^2 = 0 // : 5

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

10*x+(5*x)/(5*x^2) = 0

10*x^1+1*x^-1 = 0

(10*x^2+1*x^0)/(x^1) = 0 // * x^2

x^1*(10*x^2+1*x^0) = 0

x^1

10*x^2+1 = 0

10*x^2+1 = 0

DELTA = 0^2-(1*4*10)

DELTA = -40

DELTA < 0

x in { } 

x belongs to the empty set

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